X^2+4x+1.5=0

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Solution for X^2+4x+1.5=0 equation: 



X^2+4X+1.5=0

a = 1; b = 4; c = +1.5;
Δ = b2-4ac
Δ = 42-4·1·1.5
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{10}}{2*1}=\frac{-4-\sqrt{10}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{10}}{2*1}=\frac{-4+\sqrt{10}}{2}
$

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